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So .... You had to request my solution ?? Let number = (say) 83 Subtracting second digit leaves 80 - i.e. 10 x first digit Subtracting first digit leaves 72 i.e. 9 x first digit so .....Resulting number must ALWAYS
BE 9 x first digit: ALL these possibilities have the SAME prize. The prize table is, of course, changed for successive games. Simples Now check it out again ? Click here for: Regifting Robin
More Rigorous Solution ....... Let two digit number = n1n2 = 10*n1 + n2Subtracting n2 = 10*n1
Subtracting n1 = 9n1
Hence, resulting number must ALWAYS
BE 9 x first digit: ALL these possibilities have the SAME prize. The prize table is, of course, changed for successive games. Simples
Now check it out again ?
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